Equality of Tangents Drawn from an External Point to a Circle
What you will learn
Verify that the lengths of tangents drawn from an external point to a circle are equal (Theorem 10.2) through paper folding, Euclidean geometric construction, and RHS congruency.
Materials needed
- Drawing sheet (white chart paper)What is it?Drawing sheet (white chart paper)₹50
Tangent construction geometric acrylic kit with pre-drilled pivot holes and tangent rulers.
Specifications- Base Plate
- 250 mm × 250 mm engraved millimeter grid board
- Rods
- Two slotted acrylic tangent arms with pivot pins
- Accuracy
- ± 0.1 mm mechanical tolerances
- Geometry Box (Compass, 30 cm Metric Ruler, Protractor)What is it?Geometry Box (Compass, 30 cm Metric Ruler, Protractor)₹95
Heavy-duty steel drafting compass and ruling pens.
Specifications- Compass Length
- 160 mm with extension arm
- Divider
- 8-inch proportional divider
- Tracing paper and colored pencils setWhat is it?Tracing paper and colored pencils set₹140
Precision steel ruler with metric 0.5 mm divisions.
Specifications- Length
- 300 mm stainless steel rule
- Graduation
- 0.5 mm and 1.0 mm etched scales
- Fine craft paper-creasing toolWhat is it?Fine craft paper-creasing tool₹185
Standard laboratory apparatus used in Equality of Tangents Drawn from an External Point to a Circle.
Specifications- Category
- Mathematics Apparatus
- Grade
- CBSE / NEP 2020 Laboratory Standard
Tick items as you collect them. Tap + to see the product, specifications and buy options.
Stay safe
- Compass pivot must be sharp and tightened to prevent slipping during arc construction.
- The tangent must touch the circle at exactly one point (radius OT is strictly perpendicular to PT: ∠OTP = 90°).
- Align the ruler with hairline accuracy along the points of tangency.
- Crease paper cleanly along axis of symmetry OP for folding verification.
Steps
- 1Draw a circle of radius r = 5 cm with center O on white chart paper.Observation
Draw a circle of radius r = 5.0 cm with center O on white drawing board; mark external point P at OP = 13.0 cm.
SafetyEnsure straight line OP is measured accurately with steel rule.
- 2Choose a point P outside the circle such that distance OP = 13 cm.Observation
Find midpoint M of line OP by constructing its perpendicular bisector using compass arcs.
SafetyOpen compass to radius > half of OP to draw intersecting bisector arcs.
- 3Join OP and draw the perpendicular bisector of OP to find midpoint M.Observation
With center M and radius MP = MO = 6.5 cm, draw a circle intersecting original circle at points T1 and T2.
SafetyAnchor compass point firmly at M to prevent center slip.
- 4With M as center and radius MO = MP, draw a second circle intersecting the original circle at points T1 and T2.Observation
Join PT1 and PT2; draw radii OT1 and OT2; verify angles ∠OT1P and ∠OT2P are exactly 90.0° using set square.
SafetyA tangent to a circle is perpendicular to the radius through the point of contact.
- 5Join PT1 and PT2: these are the two tangents from external point P to the circle.Observation
Measure tangent lengths PT1 and PT2 with vernier / divider; both measure exactly 12.00 cm.
SafetyUse fine dividers to transfer lengths directly onto steel rule scale.
- 6Measure lengths PT1 and PT2 with a precision metric ruler (both measure exactly 12.0 cm: √(13² - 5²) = √(169 - 25) = √144 = 12 cm).Observation
Cut along PT1, PT2 and fold along OP: triangle ΔOPT1 superimposes perfectly onto ΔOPT2, confirming equality.
SafetyFold precisely along axis of symmetry OP.
- 7Fold the paper along line OP: observe that ray PT1 superimposes precisely on PT2, verifying equality.
Tap + on a step to see what you will observe and any safety tips.
Record your observations
| Construction Trial | Circle Radius r (cm) | Distance OP from Center (cm) | Calculated Tangent √(OP²-r²) (cm) | Measured PT1 (cm) | Measured PT2 (cm) | Difference |PT1 - PT2| (cm) |
|---|---|---|---|---|---|---|
| Trial 1 | 5.0 cm | 13.0 cm | 12.00 cm | 12.00 cm | 12.00 cm | 0.00 cm (Exact equality) |
| Trial 2 | 3.0 cm | 5.0 cm | 4.00 cm | 4.00 cm | 4.00 cm | 0.00 cm (Exact equality) |
| Trial 3 | 6.0 cm | 10.0 cm | 8.00 cm | 8.00 cm | 8.00 cm | 0.00 cm (Exact equality) |
| Trial 4 | 8.0 cm | 17.0 cm | 15.00 cm | 15.00 cm | 15.00 cm | 0.00 cm (Exact equality) |
| Trial 5 | 7.0 cm | 25.0 cm | 24.00 cm | 24.00 cm | 24.00 cm | 0.00 cm (Exact equality) |
Tap a highlighted cell to write your own observation.
Result and conclusion
Tangents PT1 and PT2 from point P measure exactly 12.0 cm each. Triangle OPT1 is congruent to Triangle OPT2 by RHS criterion, proving PT1 = PT2.
| Observation | What it means |
|---|---|
| Congruence of Right Triangles | Right triangles ΔOPT1 and ΔOPT2 are congruent by RHS criterion (OT1 = OT2 = r, OP common hypotenuse, ∠OT1P = ∠OT2P = 90°). |
| Equal Tangent Lengths Verified | Congruence directly implies PT1 = PT2 = 12.0 cm, confirming that lengths of tangents drawn from an external point are strictly equal. |
| Angle Subtension Equality | The tangents subtend equal angles at the circle center (∠T1OP = ∠T2OP = 67.38°). |
| Line of Centers Bisects Tangent Angle | Line segment OP bisects the angle between the two tangents (∠T1PO = ∠T2PO = 22.62°). |
Sample readings. Replace with your own results.